How to find the total time I spent on my laptop in this year?
Trying with bash script and extending your command.
I use dateutils
to add up the time duration.
Hence to use this script one needs the dateutils
package available through apt
. ( sudo apt install dateutils
)
This script takes into account the current uptime (present session) also, hence more accurate. Seconds are not counted. Lowest unit reported is minute.
#!/bin/bash
# Total uptime reported.
temp=$(last reboot --since 2016-01-01 --until 2016-12-31 | grep -o '(.*)' | grep -v '-' | sed 's/(\([0-9]\{1,\}\)+\([0-9]\{1,\}\):\([0-9]\{1,\}\))/\1d\2h\3m/g ;s/(\([0-9]\{1,\}\):\([0-9]\{1,\}\))/\1h\2m/g' )
curr=$( cat /proc/uptime | perl -ne '/(\d*)/ ; printf "%02d:%02d:%02d\n",int($1/86400),int(($1%86400)/3600),int(($1%3600)/60)' )
echo "Total run time (days:hours:minutes)"
curr="2015-01-01T"$curr
org="2015-01-01T00:00:00"
new=$(dateutils.dadd $curr $temp )
dateutils.ddiff $org $new -f "%dd %Hh %Mm"
- First the uptimes from last reboot is listed and formatted to extract the day, hours, minutes and second information. This is then saved in
temp
. - A reference fake date is set called org=
2015-01-01
to which current uptime is added. - Then all cumulative uptimes are added to the variable
new
- The duration between
org
and the net uptimenew
is found by difference.
Output:
vayu@helix:$ ./uptime_record.sh
Total run time (days:hours:minutes)
57d 20h 36m
The following script is for the uptime in exactly one year from the day the script is run.
#!/bin/bash
# Total uptime reported since exactly 1 year (from the time script is run).
now="$(date +'%Y-%m-%d')" ;
last_y=$(dateutils.dadd $now -1y)
temp=$(last reboot --since "$last_y" --until "$now" | grep -o '(.*)' | grep -v '-' | sed 's/(\([0-9]\{1,\}\)+\([0-9]\{1,\}\):\([0-9]\{1,\}\))/\1d\2h\3m/g ;s/(\([0-9]\{1,\}\):\([0-9]\{1,\}\))/\1h\2m/g' )
curr=$( cat /proc/uptime | perl -ne '/(\d*)/ ; printf "%02d:%02d:%02d\n",int($1/86400),int(($1%86400)/3600),int(($1%3600)/60)' )
echo "Total run time in one year (days:hours:minutes)"
curr="1980-01-01T"$curr
org="1980-01-01T00:00:00"
new=$(dateutils.dadd $curr $temp )
dateutils.ddiff $org $new -f "%dd %Hh %Mm"
Here is a python implementation of what I want, but I am sure there is an elegant way to do it with bash:
import subprocess
output = subprocess.run("last reboot --since 2016-01-01 --until 2016-12-31 | grep -o '(.*)' | grep -v '-'| sed -e 's/(//g; s/)//g; s/+/:/g'", shell=True, stdout=subprocess.PIPE, universal_newlines=True)
mins_total = 0
for line in output.stdout.split('\n')[:-1]:
try:
(hrs, mins) = [int(k) for k in line.split(':')]
days = 0
except:
(days, hrs, mins) = [int(k) for k in line.split(':')]
mins_total += (days*24 + hrs)*60 + mins
print("Hours: " + str(mins_total/60))
print("Days: " + str(mins_total/60/24))
Here's an awk + awk version:
last ... | awk '/reboot/{print $NF}' |
awk -F '[(+:)]' '
{
d += $(NF - 3); h += $(NF - 2); m += $(NF - 1)
}
END {
carry = m / 60; h += carry;
carry = h / 24; d += carry;
printf "%d days, %d hours, %d minutes\n", d, h % 24, m % 60
}'
last
's last column is in the format (<days>+hours:minutes)
, where days+
is dropped if the period is less than 1 day.
Here, the first awk
command outputs the last column, the duration of interest, for reboot
entries.
For the second awk
command:
FS
is[(+:)]
, i.e., parentheses or+
or:
. So,(h:m)
is split to,
h
,m
and(first and last fields empty), and
(d+h:m)
is split to,
d
,h
,m
and(again, first and last fields empty).
- Then we take the second-last field for minutes, third-last for hours and fourth-last for days. The fourth-last field will be the first, empty, field if days is not present. So, we'll be simply adding
0
in this case. - Then we bump up the hours and days by if minutes and hours are above 60 and 24 respectively. Note that awk does floating point division, so
h
andd
may now have fractional parts. - Then we print the numbers as integers (
%d
), so any fractional part is ignored.