How to get arguments with flags in Bash
This is the idiom I usually use:
while test $# -gt 0; do
case "$1" in
-h|--help)
echo "$package - attempt to capture frames"
echo " "
echo "$package [options] application [arguments]"
echo " "
echo "options:"
echo "-h, --help show brief help"
echo "-a, --action=ACTION specify an action to use"
echo "-o, --output-dir=DIR specify a directory to store output in"
exit 0
;;
-a)
shift
if test $# -gt 0; then
export PROCESS=$1
else
echo "no process specified"
exit 1
fi
shift
;;
--action*)
export PROCESS=`echo $1 | sed -e 's/^[^=]*=//g'`
shift
;;
-o)
shift
if test $# -gt 0; then
export OUTPUT=$1
else
echo "no output dir specified"
exit 1
fi
shift
;;
--output-dir*)
export OUTPUT=`echo $1 | sed -e 's/^[^=]*=//g'`
shift
;;
*)
break
;;
esac
done
Key points are:
$#
is the number of arguments- while loop looks at all the arguments supplied, matching on their values inside a case statement
- shift takes the first one away. You can shift multiple times inside of a case statement to take multiple values.
This example uses Bash's built-in getopts
command and is from the Google Shell Style Guide:
a_flag=''
b_flag=''
files=''
verbose='false'
print_usage() {
printf "Usage: ..."
}
while getopts 'abf:v' flag; do
case "${flag}" in
a) a_flag='true' ;;
b) b_flag='true' ;;
f) files="${OPTARG}" ;;
v) verbose='true' ;;
*) print_usage
exit 1 ;;
esac
done
Note: If a character is followed by a colon (e.g. f:
), that option is expected to have an argument.
Example usage: ./script -v -a -b -f filename
Using getopts has several advantages over the accepted answer:
- the while condition is a lot more readable and shows what the accepted options are
- cleaner code; no counting the number of parameters and shifting
- you can join options (e.g.
-a -b -c
→-abc
)
However, a big disadvantage is that it doesn't support long options, only single-character options.