How to get date in BAT file
You get and format like this
for /f "tokens=1-4 delims=/ " %%i in ("%date%") do (
set dow=%%i
set month=%%j
set day=%%k
set year=%%l
)
set datestr=%month%_%day%_%year%
echo datestr is %datestr%
Note: Above only works on US locale. It assumes the output of echo %date%
looks like this: Thu 02/13/21
. If you have different Windows locale settings, you will need to modify the script based on your configuration.
Locale-independent one liner to get any date format you like. I use it to generate archive names. Back quote (`) option is needed because PowerShell command line is using single quotes (').
:: Get date in 'yyyyMMdd_HHmm' format to use with file name.
FOR /f "usebackq" %%i IN (`PowerShell ^(Get-Date^).ToString^('yyyyMMdd_HHmm'^)`) DO SET DTime=%%i
:: Get yesterday date in 'yyyy-MM-dd' format.
FOR /f "usebackq" %%i IN (`PowerShell ^(Get-Date^).AddDays^(-1^).ToString^('yyyy-MM-dd'^)`) DO SET DTime=%%i
:: Show file name with the date.
echo Archive.%DTime%.zip
%date%
will give you the date.
%time%
will give you the time.
The date
and time /t
commands may give you more detail.
This will give you DD MM YYYY YY HH Min Sec
variables and works on any Windows machine from XP Pro and later.
@echo off
for /f "tokens=2 delims==" %%a in ('wmic OS Get localdatetime /value') do set "dt=%%a"
set "YY=%dt:~2,2%" & set "YYYY=%dt:~0,4%" & set "MM=%dt:~4,2%" & set "DD=%dt:~6,2%"
set "HH=%dt:~8,2%" & set "Min=%dt:~10,2%" & set "Sec=%dt:~12,2%"
set "datestamp=%YYYY%%MM%%DD%" & set "timestamp=%HH%%Min%%Sec%"
set "fullstamp=%YYYY%-%MM%-%DD%_%HH%-%Min%-%Sec%"
echo datestamp: "%datestamp%"
echo timestamp: "%timestamp%"
echo fullstamp: "%fullstamp%"
pause