How to merge 2 JSON objects from 2 files using jq?
Since 1.4 this is now possible with the *
operator. When given two objects, it will merge them recursively. For example,
jq -s '.[0] * .[1]' file1 file2
Important: Note the -s (--slurp)
flag, which puts files in the same array.
Would get you:
{
"value1": 200,
"timestamp": 1382461861,
"value": {
"aaa": {
"value1": "v1",
"value2": "v2",
"value3": "v3",
"value4": 4
},
"bbb": {
"value1": "v1",
"value2": "v2",
"value3": "v3"
},
"ccc": {
"value1": "v1",
"value2": "v2"
},
"ddd": {
"value3": "v3",
"value4": 4
}
},
"status": 200
}
If you also want to get rid of the other keys (like your expected result), one way to do it is this:
jq -s '.[0] * .[1] | {value: .value}' file1 file2
Or the presumably somewhat more efficient (because it doesn't merge any other values):
jq -s '.[0].value * .[1].value | {value: .}' file1 file2
Use jq -s add
:
$ echo '{"a":"foo","b":"bar"} {"c":"baz","a":0}' | jq -s add
{
"a": 0,
"b": "bar",
"c": "baz"
}
This reads all JSON texts from stdin into an array (jq -s
does that) then it "reduces" them.
(add
is defined as def add: reduce .[] as $x (null; . + $x);
, which iterates over the input array's/object's values and adds them. Object addition == merge.)
Here's a version that works recursively (using *
) on an arbitrary number of objects:
echo '{"A": {"a": 1}}' '{"A": {"b": 2}}' '{"B": 3}' |\
jq --slurp 'reduce .[] as $item ({}; . * $item)'
{
"A": {
"a": 1,
"b": 2
},
"B": 3
}
Who knows if you still need it, but here is the solution.
Once you get to the --slurp
option, it's easy!
--slurp/-s:
Instead of running the filter for each JSON object in the input,
read the entire input stream into a large array and run the filter just once.
Then the +
operator will do what you want:
jq -s '.[0] + .[1]' config.json config-user.json
(Note: if you want to merge inner objects instead of just overwriting the left file ones with the right file ones, you will need to do it manually)