how to set a background color in UIimage in swift programming
You can also use this extension:
extension UIImage {
func imageWithColor(tintColor: UIColor) -> UIImage {
UIGraphicsBeginImageContextWithOptions(self.size, false, self.scale)
let context = UIGraphicsGetCurrentContext()!
context.translateBy(x: 0, y: self.size.height)
context.scaleBy(x: 1.0, y: -1.0);
context.setBlendMode(.normal)
let rect = CGRect(x: 0, y: 0, width: self.size.width, height: self.size.height) as CGRect
context.clip(to: rect, mask: self.cgImage!)
tintColor.setFill()
context.fill(rect)
let newImage = UIGraphicsGetImageFromCurrentImageContext()!
UIGraphicsEndImageContext()
return newImage
}
}
And then
image.imageWithColor("#1A6BAE".UIColor)
EDIT: 2019-11: Updated to Swift 5 by @Yuto
Updated @Egghead's solution for Swift 3
extension UIImage {
static func imageWithColor(tintColor: UIColor) -> UIImage {
let rect = CGRect(x: 0, y: 0, width: 1, height: 1)
UIGraphicsBeginImageContextWithOptions(rect.size, false, 0)
tintColor.setFill()
UIRectFill(rect)
let image: UIImage = UIGraphicsGetImageFromCurrentImageContext()!
UIGraphicsEndImageContext()
return image
}
}
Usage :
UIImage.imageWithColor(tintColor: <Custom color>)
Swift 5, 4
If you need to draw the background of an image, for optimization and decorative purposes, you can draw the image in a specific way:
UIImage(named: "someImage")?.withBackground(color: .white)
Extension
extension UIImage {
func withBackground(color: UIColor, opaque: Bool = true) -> UIImage {
UIGraphicsBeginImageContextWithOptions(size, opaque, scale)
guard let ctx = UIGraphicsGetCurrentContext(), let image = cgImage else { return self }
defer { UIGraphicsEndImageContext() }
let rect = CGRect(origin: .zero, size: size)
ctx.setFillColor(color.cgColor)
ctx.fill(rect)
ctx.concatenate(CGAffineTransform(a: 1, b: 0, c: 0, d: -1, tx: 0, ty: size.height))
ctx.draw(image, in: rect)
return UIGraphicsGetImageFromCurrentImageContext() ?? self
}
}