How to stop a goroutine

You can't kill a goroutine from outside. You can signal a goroutine to stop using a channel, but there's no handle on goroutines to do any sort of meta management. Goroutines are intended to cooperatively solve problems, so killing one that is misbehaving would almost never be an adequate response. If you want isolation for robustness, you probably want a process.

Typically, you pass the goroutine a (possibly separate) signal channel. That signal channel is used to push a value into when you want the goroutine to stop. The goroutine polls that channel regularly. As soon as it detects a signal, it quits.

quit := make(chan bool)
go func() {
    for {
        select {
        case <- quit:
            return
        default:
            // Do other stuff
        }
    }
}()

// Do stuff

// Quit goroutine
quit <- true

EDIT: I wrote this answer up in haste, before realizing that your question is about sending values to a chan inside a goroutine. The approach below can be used either with an additional chan as suggested above, or using the fact that the chan you have already is bi-directional, you can use just the one...

If your goroutine exists solely to process the items coming out of the chan, you can make use of the "close" builtin and the special receive form for channels.

That is, once you're done sending items on the chan, you close it. Then inside your goroutine you get an extra parameter to the receive operator that shows whether the channel has been closed.

Here is a complete example (the waitgroup is used to make sure that the process continues until the goroutine completes):

package main

import "sync"
func main() {
    var wg sync.WaitGroup
    wg.Add(1)

    ch := make(chan int)
    go func() {
        for {
            foo, ok := <- ch
            if !ok {
                println("done")
                wg.Done()
                return
            }
            println(foo)
        }
    }()
    ch <- 1
    ch <- 2
    ch <- 3
    close(ch)

    wg.Wait()
}

Generally, you could create a channel and receive a stop signal in the goroutine.

There two way to create channel in this example.

1. channel

2. context. In the example I will demo context.WithCancel

The first demo, use channel:

package main

import "fmt"
import "time"

func do_stuff() int {
    return 1
}

func main() {

    ch := make(chan int, 100)
    done := make(chan struct{})
    go func() {
        for {
            select {
            case ch <- do_stuff():
            case <-done:
                close(ch)
                return
            }
            time.Sleep(100 * time.Millisecond)
        }
    }()

    go func() {
        time.Sleep(3 * time.Second)
        done <- struct{}{}
    }()

    for i := range ch {
        fmt.Println("receive value: ", i)
    }

    fmt.Println("finish")
}

The second demo, use context:

package main

import (
    "context"
    "fmt"
    "time"
)

func main() {
    forever := make(chan struct{})
    ctx, cancel := context.WithCancel(context.Background())

    go func(ctx context.Context) {
        for {
            select {
            case <-ctx.Done():  // if cancel() execute
                forever <- struct{}{}
                return
            default:
                fmt.Println("for loop")
            }

            time.Sleep(500 * time.Millisecond)
        }
    }(ctx)

    go func() {
        time.Sleep(3 * time.Second)
        cancel()
    }()

    <-forever
    fmt.Println("finish")
}