Converting a YAML file to Python JSON object
The PyYAML library is intended for this purpose
pip install pyyaml
import yaml
import json
with open("example.yaml", 'r') as yaml_in, open("example.json", "w") as json_out:
yaml_object = yaml.safe_load(yaml_in) # yaml_object will be a list or a dict
json.dump(yaml_object, json_out)
Notes: PyYAML only supports the pre-2009, YAML 1.1 specification.
ruamel.yaml is an option if YAML 1.2 is required.
pip install ruamel.yaml
you can use PyYAML
pip install PyYAML
And in the ipython console:
In [1]: import yaml
In [2]: document = """Section:
...: heading: Heading 1
...: font:
...: name: Times New Roman
...: size: 22
...: color_theme: ACCENT_2
...:
...: SubSection:
...: heading: Heading 3
...: font:
...: name: Times New Roman
...: size: 15
...: color_theme: ACCENT_2
...: Paragraph:
...: font:
...: name: Times New Roman
...: size: 11
...: color_theme: ACCENT_2
...: Table:
...: style: MediumGrid3-Accent2"""
...:
In [3]: yaml.load(document)
Out[3]:
{'Paragraph': {'font': {'color_theme': 'ACCENT_2',
'name': 'Times New Roman',
'size': 11}},
'Section': {'font': {'color_theme': 'ACCENT_2',
'name': 'Times New Roman',
'size': 22},
'heading': 'Heading 1'},
'SubSection': {'font': {'color_theme': 'ACCENT_2',
'name': 'Times New Roman',
'size': 15},
'heading': 'Heading 3'},
'Table': {'style': 'MediumGrid3-Accent2'}}