How can I get dict from sqlite query?

You could use row_factory, as in the example in the docs:

import sqlite3

def dict_factory(cursor, row):
    d = {}
    for idx, col in enumerate(cursor.description):
        d[col[0]] = row[idx]
    return d

con = sqlite3.connect(":memory:")
con.row_factory = dict_factory
cur = con.cursor()
cur.execute("select 1 as a")
print cur.fetchone()["a"]

or follow the advice that's given right after this example in the docs:

If returning a tuple doesn’t suffice and you want name-based access to columns, you should consider setting row_factory to the highly-optimized sqlite3.Row type. Row provides both index-based and case-insensitive name-based access to columns with almost no memory overhead. It will probably be better than your own custom dictionary-based approach or even a db_row based solution.

Here is the code for this second solution:

con = sqlite3.connect(…)
con.row_factory = sqlite3.Row   #   add this row
cursor = con.cursor()

I thought I answer this question even though the answer is partly mentioned in both Adam Schmideg's and Alex Martelli's answers. In order for others like me that have the same question, to find the answer easily.

conn = sqlite3.connect(":memory:")

#This is the important part, here we are setting row_factory property of
#connection object to sqlite3.Row(sqlite3.Row is an implementation of
#row_factory)
conn.row_factory = sqlite3.Row
c = conn.cursor()
c.execute('select * from stocks')

result = c.fetchall()
#returns a list of dictionaries, each item in list(each dictionary)
#represents a row of the table