Javascript arguments.sort() throw error sort is not a function

Another way to do this is by declaring the arguments as an array.

var myArguments = [1, 1, 2, 3];
var sortedArguments = [];

Thus the highest() can be defined as;

function highest(myArguments)
{ 
  return myArguments.sort(function(a,b)
  { 
    return b - a; 
  }); 
}
sortedArguments = highest(myArguments); 

Because arguments has no sort method. Be aware that arguments is not an Array object, it's an array-like Arguments object.

However, you can use Array.prototype.slice to convert arguments to an array; and then you will be able to use Array.prototype.sort:

function highest(){ 
  return [].slice.call(arguments).sort(function(a,b){ 
    return b - a; 
  }); 
}
highest(1, 1, 2, 3); // [3, 2, 1, 1]

use spread syntax to convert arguments to a real Array:

   function highest(...arguments){ 
      return arguments.sort(function(a,b){ 
        return b - a; 
      }); 
   }
   highest(1, 1, 2, 3);

Output: (4) [3, 2, 1, 1]