List minimum in Python with None?

None is being returned

>>> print min([None, 1,2])
None
>>> None < 1
True

If you want to return 1 you have to filter the None away:

>>> L = [None, 1, 2]
>>> min(x for x in L if x is not None)
1

using a generator expression:

>>> min(value for value in [None,1,2] if value is not None)
1

eventually, you may use filter:

>>> min(filter(lambda x: x is not None, [None,1,2]))
1