Pass Parameter with UITapGestureRecognizer
One approach would be to subclass UITapGestureRecognizer and then set a property, I've posted an example below. You could also do some check on the sender and check if equal to some tag, class, string, e.t.c
class ViewController: UIViewController {
@IBOutlet weak var label1: UILabel!
@IBOutlet weak var image: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
image.userInteractionEnabled = true;
let tappy = MyTapGesture(target: self, action: #selector(self.tapped(_:)))
image.addGestureRecognizer(tappy)
tappy.title = "val"
}
func tapped(sender : MyTapGesture) {
print(sender.title)
label1.text = sender.title
}
}
class MyTapGesture: UITapGestureRecognizer {
var title = String()
}
There are lots of examples on SO, have a look, good luck.
For Swift 4
In Viewdidload
let label = UILabel(frame: CGRect(x: 0, y: h, width: Int(self.phoneNumberView.bounds.width), height: 30))
label.textColor = primaryColor
label.numberOfLines = 0
label.font = title3Font
label.lineBreakMode = .byWordWrapping
label.attributedText = fullString
let phoneCall = MyTapGesture(target: self, action: #selector(self.openCall))
phoneCall.phoneNumber = "\(res)"
label.isUserInteractionEnabled = true
label.addGestureRecognizer(phoneCall)
Function as
@objc func openCall(sender : MyTapGesture) {
let number = sender.phoneNumber
print(number)
}
Write Class as
class MyTapGesture: UITapGestureRecognizer {
var phoneNumber = String()
}