Set Union in pandas

For these operations pure Python is generally more efficient.

%timeit pd.Series([set1.union(set2) for set1, set2 in zip(df['A'], df['B'])])
10 loops, best of 3: 43.3 ms per loop

%timeit df.apply(lambda x: x.A.union(x.B), axis=1)
1 loop, best of 3: 2.6 s per loop

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DataFrame for timings:

import pandas as pd
import numpy as np
l1 = [set(np.random.choice(list('abcdefg'), np.random.randint(1, 5))) for _ in range(100000)]
l2 = [set(np.random.choice(list('abcdefg'), np.random.randint(1, 5))) for _ in range(100000)]

df = pd.DataFrame({'A': l1, 'B': l2})

This is the best I could come up with:

# method 1
df.apply(lambda x: x.set1.union(x.set2), axis=1)

# method 2
df.applymap(list).sum(1).apply(set)

Wow!

I expected the method 2 to be quicker. Not so!

Example

df = pd.DataFrame([[{1, 2, 3}, {3, 4, 5}] for _ in range(3)],
                  columns=list('AB'))
df

df.apply(lambda x: x.set1.union(x.set2), axis=1)

0    {1, 2, 3, 4, 5}
1    {1, 2, 3, 4, 5}
2    {1, 2, 3, 4, 5}