Is it possible to multiprocess a function that returns something in Python?
Yes, sure - you can use a number of methods. One of the easiest ones is a shared Queue
. See an example here: http://eli.thegreenplace.net/2012/01/16/python-parallelizing-cpu-bound-tasks-with-multiprocessing/
I'm copying this example straight from the docs because I can't give you a direct link to it. Note that it prints out the results from the done_queue, but you can do whatever you like with it.
#
# Simple example which uses a pool of workers to carry out some tasks.
#
# Notice that the results will probably not come out of the output
# queue in the same in the same order as the corresponding tasks were
# put on the input queue. If it is important to get the results back
# in the original order then consider using `Pool.map()` or
# `Pool.imap()` (which will save on the amount of code needed anyway).
#
# Copyright (c) 2006-2008, R Oudkerk
# All rights reserved.
#
import time
import random
from multiprocessing import Process, Queue, current_process, freeze_support
#
# Function run by worker processes
#
def worker(input, output):
for func, args in iter(input.get, 'STOP'):
result = calculate(func, args)
output.put(result)
#
# Function used to calculate result
#
def calculate(func, args):
result = func(*args)
return '%s says that %s%s = %s' % \
(current_process().name, func.__name__, args, result)
#
# Functions referenced by tasks
#
def mul(a, b):
time.sleep(0.5*random.random())
return a * b
def plus(a, b):
time.sleep(0.5*random.random())
return a + b
#
#
#
def test():
NUMBER_OF_PROCESSES = 4
TASKS1 = [(mul, (i, 7)) for i in range(20)]
TASKS2 = [(plus, (i, 8)) for i in range(10)]
# Create queues
task_queue = Queue()
done_queue = Queue()
# Submit tasks
for task in TASKS1:
task_queue.put(task)
# Start worker processes
for i in range(NUMBER_OF_PROCESSES):
Process(target=worker, args=(task_queue, done_queue)).start()
# Get and print results
print 'Unordered results:'
for i in range(len(TASKS1)):
print '\t', done_queue.get()
# Add more tasks using `put()`
for task in TASKS2:
task_queue.put(task)
# Get and print some more results
for i in range(len(TASKS2)):
print '\t', done_queue.get()
# Tell child processes to stop
for i in range(NUMBER_OF_PROCESSES):
task_queue.put('STOP')
if __name__ == '__main__':
freeze_support()
test()
It is originally from the multiprocessing module docs.
You are looking to do some embarrassingly parallel work using multiple processes, so why not use a Pool
? A Pool
will take care of starting up the processes, retrieving the results, and returning the results to you.
I use pathos
, which has a fork of multiprocessing
, because it has much better serialization than the version that standard library provides.
(.py) file
from pathos.multiprocessing import ProcessingPool as Pool
def foo(obj1, obj2):
a = obj1.x**2
b = obj2.x**2
return a,b
class Bar(object):
def __init__(self, x):
self.x = x
Pool().map(foo, [Bar(1),Bar(2),Bar(3)], [Bar(4),Bar(5),Bar(6)])
Result
[(1, 16), (4, 25), (9, 36)]
And you see that foo
takes two arguments, and returns a tuple of two objects. The map
method of Pool
submits foo
to the underlying processes and returns the result as res
.
You can get pathos
here: https://github.com/uqfoundation
Why nobody uses callback of multiprocessing.Pool?
Example:
from multiprocessing import Pool
from contextlib import contextmanager
from pprint import pprint
from requests import get as get_page
@contextmanager
def _terminating(thing):
try:
yield thing
finally:
thing.terminate()
def _callback(*args, **kwargs):
print("CALBACK")
pprint(args)
pprint(kwargs)
print("Processing...")
with _terminating(Pool(processes=WORKERS)) as pool:
results = pool.map_async(get_page, URLS, callback=_callback)
start_time = time.time()
results.wait()
end_time = time.time()
print("Time for Processing: %ssecs" % (end_time - start_time))
Here, I print both args and kwargs. But you can replace callback by:
def _callback2(responses):
for r in responses:
print(r.status_code) # or do whatever with response...