Java run code only if no exception is thrown in try and catch block?

try {
    doSomething();
    doSomething2();
} catch (Exception e) {
    doSomething3();
}

In this example, doSomething2() will only be executed if no exception is thrown by doSomething().

If an exception is thrown by doSomething(), doSomething2(); will be skipped and execution will jump to doSomething3();

Also note, doSomething3() will be executed if there is an exception thrown by doSomething2();

If no exception is thrown, doSomething3(); will not be executed.

Here are two ways:

try {
    somethingThatMayThrowAnException();
    somethingElseAfterwards();
} catch (...) {
    ...
}

Or if you want your second block of code to be outside the try block:

boolean success = false;
try {
    somethingThatMayThrowAnException();
    success = true;
} catch (...) {
    ...
}
if (success) {
    somethingElseAfterwards();
}

You could also put the if statement in a finally block, but there is not enough information in your question to tell if that would be preferable or not.