how to sort id's of array of objects in javascript code example

Example 1: javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first

Example 2: javascript sort array of objects

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

compareObjects(object1, object2, key) {
  const obj1 = object1[key].toUpperCase()
  const obj2 = object2[key].toUpperCase()

  if (obj1 < obj2) {
    return -1
  }
  if (obj1 > obj2) {
    return 1
  }
  return 0
}

books.sort((book1, book2) => {
  return compareObjects(book1, book2, 'name')
})

// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}

Example 3: javascript sort array of objects

// Handles mix-cased strings and numbers with option for setting order
const sortObjectArray = ({ arr, field, order = 'desc' }) => {
   arr.sort(function(a, b) {
      const fieldA = typeof a[field] === 'string' ? a[field].toLowerCase() : a[field]
      const fieldB = typeof b[field] === 'string' ? b[field].toLowerCase() : b[field]

      let result
      if (order === 'desc') {
         result = fieldA > fieldB ? 1 : -1
      } else {
         result = fieldA < fieldB ? 1 : -1
      }
      return result
   })
   return arr
}

let arr = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "jake", age: 25}
]

let arr2 = sortObjectArray({ arr, field: 'name'})
console.log(arr2)
/*
[
{ age: 25, name: "jake"}, 
{ age: 34, name: "John" }, 
{ age: 54, name: "Peter" }
]
*/

let arr3 = sortObjectArray({ arr, field: 'age', order: 'asc' })
console.log(arr3)
/*
[
{ age: 54, name: "Peter" },
{ age: 34, name: "John" }, 
{ age: 25, name: "jake"}
]
*/