Kotlin get type as string
There is a simpler way using simpleName
property and avoiding Kotlin prefix.
val lis = listOf(1,2,3)
lis
is from type ArrayList
. So one can use
println(lis.javaClass.kotlin.simpleName) // ArrayList
or, more elegantly:
println(lis::class.simpleName) // ArrayList
You can use one of the methods that best suits your needs:
val obj: Double = 5.0
System.out.println(obj.javaClass.name) // double
System.out.println(obj.javaClass.kotlin) // class kotlin.Double
System.out.println(obj.javaClass.kotlin.qualifiedName) // kotlin.Double
You can fiddle with this here.