List of lists of lists how to make a map recursively

Not very pretty but shorter:

foo // ClearAll
foo[list_List] := Module[{res}
, Sow @ MapIndexed[ If[ListQ @ #, Append[#2, Length @ #], #] &, list]
; foo /@ list; 
]

Column @ Reap[foo@list][[-1, 1]]

{ab,ad,{3,4},aw}
{be,br,pb,{4,8}}
{cd,cr,ce,{4,1},{5,4},ne,{7,3},{8,4}}
{fo}
{gf,gh,gv,gg}
{ks,kd,kl}
{sa,sx,sr,{4,5}}
{sdr,svd,{3,2},{4,3},ja}
{ssfrt,styi}
{sfc,sfb,smaa}

p.s. I don't like the fact that foo needs to map list twice but otherwise the order is wrong.

ClearAll[f0, tdl1, tdl2]
f0 = Replace[#, x_List :> Flatten[{Position[#, x], Length @ x}], 1] &;

You can use f0 with Extract:

tdl1 = Extract[#, Sort@Position[#, _List], f0] &; 
tdl1 @ list // Column // TeXForm

$\begin{array}{l} \{\text{ab},\text{ad},\{3,4\},\text{aw}\} \\ \{\text{be},\text{br},\text{pb},\{4,8\}\} \\ \{\text{cd},\text{cr},\text{ce},\{4,1\},\{5,4\},\text{ne},\{7,3\},\{8,4\}\} \\ \{\text{fo}\} \\ \{\text{gf},\text{gh},\text{gv},\text{gg}\} \\ \{\text{ks},\text{kd},\text{kl}\} \\ \{\text{sa},\text{sx},\text{sr},\{4,5\}\} \\ \{\text{sdr},\text{svd},\{3,2\},\{4,3\},\text{ja}\} \\ \{\text{ssfrt},\text{styi}\} \\ \{\text{sfc},\text{sfb},\text{smaa}\} \\ \end{array}$

or withTable:

tdl2 = Table[f0[#[[## & @@ i]]], {i, Sort@Position[#, _List]}] &;
tdl1@list == tdl2@list

True