Max in a list with two conditions

You have to both filter and use a key argument to max:

from operator import itemgetter

max(filter(lambda a: a[2] >= 100, yourlist), key=itemgetter(1))

The filter can also be expressed as a generator expression:

max((t for t in yourlist if t[2] >= 100), key=itemgetter(1))

Demo:

>>> yourlist = [(1, 2, 300), (2, 3, 400), (3, 6, 50)]
>>> max((t for t in yourlist if t[2] >= 100), key=itemgetter(1))
(2, 3, 400)
>>> max(filter(lambda a: a[2] >= 100, yourlist), key=itemgetter(1))
(2, 3, 400)

Note that because you filter, it's easy to end up with an empty list to pick the max from, so you may need to catch ValueErrors unless you need that exception to propagate up the call stack:

try:
    return max(filter(lambda a: a[2] >= 100, yourlist), key=itemgetter(1))
except ValueError:
    # Return a default
    return (0, 0, 0)