Move sign under exponent
I could understand a desire to avoid the hole, but your readers would have a hard time in interpreting the expression if the exponent is completely above \times
.
I'd possibly use (3) or (4), but would prefer (5), removing the \times
altogether, or better yet (6).
Notice the \!
in the exponent to avoid the other hole.
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}\times\frac{1}{(2k+2)(2k+1)}
\end{equation}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}
\mspace{-\medmuskip}
\times \frac{1}{(2k+2)(2k+1)}
\end{equation}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}
\mspace{-1.5\medmuskip}
\times \frac{1}{(2k+2)(2k+1)}
\end{equation}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}
\mspace{-2\medmuskip}
\times \frac{1}{(2k+2)(2k+1)}
\end{equation}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}
\frac{1}{(2k+2)(2k+1)}
\end{equation}
\begin{equation}
\frac{1}{(2k+2)(2k+1)}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\!k+1}
\end{equation}
\end{document}
I personally would not do that but since you are asking...
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{mathtools}
\usepackage{amsmath}
\usepackage{amsthm}
\begin{document}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\mathrlap{k+1}} \times \frac{1}{(2k+2)(2k+1)}
\end{equation}
\end{document}
I'm not sure if this is what you mean, but you can do this with the \rlap
command.
Here is the code:
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{mathtools}
\usepackage{amsmath}
\usepackage{amsthm}
\begin{document}
\begin{equation}
\left(\frac{k+1}{k^\frac{k}{k+1}}\right)^{\rlap{$\scriptstyle{k+1}$}} \times \frac{1}{(2k+2)(2k+1)}
\end{equation}
\end{document}