Neither BindingResult nor plain target object for bean name available as request attribute
In the controller, you need to add the login object as an attribute of the model:
model.addAttribute("login", new Login());
Like this:
@RequestMapping(value = "/", method = RequestMethod.GET)
public String displayLogin(Model model) {
model.addAttribute("login", new Login());
return "login";
}
You would have got this Exception while doing a GET
on http://localhost:8080/projectname/login
As Vinay has correctly stated you can definitely use
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String displayLogin(Model model) {
model.addAttribute("login", new Login());
return "login";
}
But I am going to provide some alternative syntax which I think you were trying with Spring 3.0.
You can also achieve the above functionality with
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String displayLogin(Login loginModel) {
return "login";
}
and it login.jsp
(assuming you are using InternalResourceViewResolver
) you can have
<form:form method="POST" action="login.htm" modelAttribute="login">
Notice : modelAttribute is login
and not loginModel
. It is as per the class name you provide in argument. But if you want to use loginModel
as modelAttribute is jsp you can do the following
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String displayLogin(@ModelAttribute("loginModel")Login loginModel) {
return "login";
}
and jsp would have
<form:form method="POST" action="login.htm" modelAttribute="loginModel">
I know there are just different ways for doing the same thing. But the most important point to note here -
Imp Note: When you add your model class in your methods argument (like public String displayLogin(Login loginModel)
) it is automatically created and added to your Model object (which is why you can directly access it in JSP without manually putting it in model). Then it will search your request if request has attributes that it can map with the new ModelObject create. If yes Spring will inject values from request parameters to your custom model object class (Login in this case).
You can test this by doing
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String displayLogin(Login loginModel, Model model) {
System.out.println(model.asMap().get("login").equals(loginModel));
return "login";
}
Note : Above creating of new custom model object may not hold true if you have given @SessionAttributes({"login"})
. In this case it will get from session and populate values.
the first time when you are returning your form make sure you pass the model attribute the form requires which can be done by adding the below code
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String login(Login login)
return "test";
}
By default the model attribute name is taken as Bean class's name with first lowercase letter
By doing this the form which expects a backing object naming "login" will be made available to it
after the form is submitted you can do the validation by passing your bean object and bindingresult as the method parameters as shown below
@RequestMapping(value = "/login", method = RequestMethod.POST)
public String login( @ModelAttribute("login") Login login,
BindingResult result)