Pandas histogram df.hist() group by

This is not the most flexible workaround but will work for your question specifically.

def sephist(col):
    yes = df[df['group'] == 'yes'][col]
    no = df[df['group'] == 'no'][col]
    return yes, no

for num, alpha in enumerate('abcd'):
    plt.subplot(2, 2, num)
    plt.hist(sephist(alpha)[0], bins=25, alpha=0.5, label='yes', color='b')
    plt.hist(sephist(alpha)[1], bins=25, alpha=0.5, label='no', color='r')
    plt.legend(loc='upper right')
    plt.title(alpha)
plt.tight_layout(pad=0.4, w_pad=0.5, h_pad=1.0)

You could make this more generic by:

• adding a df and by parameter to sephist: def sephist(df, by, col)
• making the subplots loop more flexible: for num, alpha in enumerate(df.columns)

Because the first argument to matplotlib.pyplot.hist can take

either a single array or a sequency of arrays which are not required to be of the same length

...an alternattive would be:

for num, alpha in enumerate('abcd'):
    plt.subplot(2, 2, num)
    plt.hist((sephist(alpha)[0], sephist(alpha)[1]), bins=25, alpha=0.5, label=['yes', 'no'], color=['r', 'b'])
    plt.legend(loc='upper right')
    plt.title(alpha)
plt.tight_layout(pad=0.4, w_pad=0.5, h_pad=1.0)

Using Seaborn

If you are open to use Seaborn, a plot with multiple subplots and multiple variables within each subplot can easily be made using seaborn.FacetGrid.

import numpy as np; np.random.seed(1)
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt

df = pd.DataFrame(np.random.randn(300,4), columns=list("ABCD"))
df["group"] = np.random.choice(["yes", "no"], p=[0.32,0.68],size=300)

df2 = pd.melt(df, id_vars='group', value_vars=list("ABCD"), value_name='value')

bins=np.linspace(df2.value.min(), df2.value.max(), 10)
g = sns.FacetGrid(df2, col="variable", hue="group", palette="Set1", col_wrap=2)
g.map(plt.hist, 'value', bins=bins, ec="k")

g.axes[-1].legend()
plt.show()