Passing all arguments of a function to another function

As others have said, using locals() might cause you to pass on more variables than intended, if func1() creates new variables before calling func2().

This is can be circumvented by calling locals() as the first thing, like so:

def func1(a=1, b=2,c=3):
    par = locals()

    d = par["a"] + par["b"]

    func2(**par)

Explicit is better than implicit but if you really don't want to type a few characters:

def func1(a=1, b=2, c=3):
    func2(**locals())

locals() are all local variables, so you can't set any extra vars before calling func2 or they will get passed too.

Provided that the arguments to func1 are only keyword arguments, you could do this:

def func1(a=1, b=2, c=3):
    func2(**locals())