Passing any function as template parameter

I believe shortening this is currently impossible. A year ago, the C++ committee looked at http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2013/n3601.html to fix this, and they encouraged the authors to pursue it further after C++14 was released.

It's now possible in C++17 with template<auto>:

template<auto Func>
struct FuncWrapper final
{
    template<typename... Args>
    auto operator()(Args &&... args) const
    {
        return Func(std::forward<Args>(args)...);
    }
};

int add(int a, int b)
{
    return a + b;
}

int main()
{
    FuncWrapper<add> wrapper;
    return wrapper(12, 34);
}

Demo: https://godbolt.org/g/B7W56t

You can use #ifdef __cpp_nontype_template_parameter_auto to detect compiler support for this in your code.

If you are able to use C++20 and you want better error messages, you can also use concepts:

template<typename T>
concept CanAddTwoNumbers = std::is_invocable_r_v<int, T, int, int>;

template<auto Func>
    requires CanAddTwoNumbers<decltype(Func)>
struct AddTwoNumbersWrapper final
{
    auto operator()(int a, int b) const
    -> int
    {
        return std::invoke(Func, a, b);
    }
};

int add(int a, int b)
{
    return a + b;
}

int main()
{
    AddTwoNumbersWrapper<add> wrapper;
    return wrapper(12, 34);
    AddTwoNumbersWrapper<123> bad; //error: constraint failure
}

Demo: https://gcc.godbolt.org/z/ai3WGH