'Pretty print' windows %PATH% variable - how to split on ';' in CMD shell
The simple way is to use
for %a in ("%path:;=";"%") do @echo %~a
This works for all without ;
in the path and without "
around a single element
Tested with path=C:\qt\4.6.3\bin;C:\Program Files;C:\documents & Settings
But a "always" solution is a bit complicated
EDIT: Now a working variant
@echo off
setlocal DisableDelayedExpansion
set "var=foo & bar;baz<>gak;"semi;colons;^&embedded";foo again!;throw (in) some (parentheses);"unmatched ;-)";(too"
set "var=%var:"=""%"
set "var=%var:^=^^%"
set "var=%var:&=^&%"
set "var=%var:|=^|%"
set "var=%var:<=^<%"
set "var=%var:>=^>%"
set "var=%var:;=^;^;%"
rem ** This is the key line, the missing quote is intended
set var=%var:""="%
set "var=%var:"=""%"
set "var=%var:;;="";""%"
set "var=%var:^;^;=;%"
set "var=%var:""="%"
set "var=%var:"=""%"
set "var=%var:"";""=";"%"
set "var=%var:"""="%"
setlocal EnableDelayedExpansion
for %%a in ("!var!") do (
endlocal
echo %%~a
setlocal EnableDelayedExpansion
)
What did I do there?
I tried to solve the main problem: that the semicolons inside of quotes should be ignored, and only the normal semicolons should be replaced with ";"
I used the batch interpreter itself to solve this for me.
- First I have to make the string safe, escaping all special characters.
- Then all
;
are replaced with^;^;
- and then the trick begins with the line
set var=%var:"=""%"
(The missing quote is the key!).
This expands in a way such that all escaped characters will lose their escape caret:var=foo & bar;;baz<>gak;;"semi^;^;colons^;^;^&embedded";;foo again!;;
...
But only outside of the quotes, so now there is a difference between semicolons outside of quotes;;
and inside^;^;
.
Thats the key.
A simple one liner to prettying printing the PATH
environment variable:
ECHO.%PATH:;= & ECHO.%
If your PATH
was equal to A;B;C
the above string substitution will change this to ECHO.A & ECHO.B & ECHO.C
and execute it all in one go. The full stop prevents the "ECHO is on" messages from appearing.