Printing Out The Value Of An XSL Variable

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Can someone please tell me how to print out a variable in my XSL transform? Seems like an easy enough thing to do but I just can't seem to do it.

In XSLT 1.0 there are two main ways of producing the contents of an <xsl:variable>, depending on whether it contains a scalar value (string, number or boolean), or has a structured value -- a node-set (one or more nodes from xml document(s) ):

  1. <xsl:value-of select="$yourscalarVariableName"/> Use this to produce a scalar value. Actually produces a text node, containing this scalar value.

  2. <xsl:copy-of select="$yourStructuredVariableName"/> Use this to produce a copy of all nodes contained in the variable.

It is very important to know that if an xsl:variable contains a list of nodes and the <xsl:value-of ...> instruction is used, only the string value of the first node will be produced. This is a frequently committed error and a FAQ.

There is a third way: if the <xsl:variable> should be used in producing an attribute:

  <someLiteralResultElement someAttribute="{$theVariable}"/>

The XPath expression in the curly braces (called AVT -- attribute-value-template) is evaluated and the result is put into the attribute value.

In XSLT 2.0, the <xsl:value-of .../> instruction , when run not in compatibility mode, produces a list of text nodes -- one for each node contained in the xsl:variable. When run in compatibility mode (has the attribute version="1.0" specified), the <xsl:value-of> instruction behaves in the same way as it does in XSLT 1.0.

In Xslt 2.0 <xsl:copy-of> behaves in the same way as in XSLT 1.0. However it is recommended to use the new <xsl:sequence> instruction, because the former produces a new copy of every node, while <xsl:sequence> does not produce new copies of nodes.


You can use:

<xsl:value-of select="$xmlElem" />

Try this:

<xsl:value-of select="$xmlElem"/>

Tags:

Xml

Xslt