Programmatically set image to UIImageView with Xcode 6.1/Swift

How about this;

myImageView.image=UIImage(named: "image_1")

where image_1 is within the assets folder as image_1.png.

This worked for me since i'm using a switch case to display an image slide.

In xcode 8 you can directly choose image from the selection window (NEW)...

• You just need to type - "image" and you will get a suggestion box then select -"Image Literal" from list (see in attached picture) and

• then tap on the square you will be able to see all images(see in
  second attached picture) which are in your image assets... or select other image from there.

• Now tap on square box - (You will see that square box after selecting above option)

Since you have your bgImage assigned and linked as an IBOutlet, there is no need to initialize it as a UIImageView... instead all you need to do is set the image property like bgImage.image = UIImage(named: "afternoon"). After running this code, the image appeared fine since it was already assigned using the outlet.

However, if it wasn't an outlet and you didn't have it already connected to a UIImageView object on a storyboard/xib file, then you could so something like the following...

class ViewController: UIViewController {
    var bgImage: UIImageView?

    override func viewDidLoad() {
        super.viewDidLoad()

        var image: UIImage = UIImage(named: "afternoon")!
        bgImage = UIImageView(image: image)
        bgImage!.frame = CGRectMake(0,0,100,200)
        self.view.addSubview(bgImage!)
    }
}

OK, got it working with this (creating the UIImageView programmatically):

var imageViewObject :UIImageView

imageViewObject = UIImageView(frame:CGRectMake(0, 0, 600, 600))

imageViewObject.image = UIImage(named:"afternoon")

self.view.addSubview(imageViewObject)

self.view.sendSubviewToBack(imageViewObject)