Python converting *args to list
There is this piece of code that I picked up in sentdex tutorials that deals with this:
https://www.youtube.com/watch?v=zPp80YM2v7k&index=11&list=PLQVvvaa0QuDcOdF96TBtRtuQksErCEBYZ
Try this:
def test_args(*args):
lists = [item for item in args]
print lists
test_args('Sun','Rain','Storm','Wind')
Result:
['Sun', 'Rain', 'Storm', 'Wind']
Nothing too magic:
def __init__(self, *args):
Parent.__init__(self, list(args))
Inside of __init__
, the variable args
is just a tuple with any arguments that were passed in. In fact you can probably just use Parent.__init__(self, args)
unless you really need it to be a list.
As a side note, using super()
is preferable to Parent.__init__()
.