Python difflib: highlighting differences inline?
For your simple example:
import difflib
def show_diff(seqm):
"""Unify operations between two compared strings
seqm is a difflib.SequenceMatcher instance whose a & b are strings"""
output= []
for opcode, a0, a1, b0, b1 in seqm.get_opcodes():
if opcode == 'equal':
output.append(seqm.a[a0:a1])
elif opcode == 'insert':
output.append("<ins>" + seqm.b[b0:b1] + "</ins>")
elif opcode == 'delete':
output.append("<del>" + seqm.a[a0:a1] + "</del>")
elif opcode == 'replace':
raise NotImplementedError("what to do with 'replace' opcode?")
else:
raise RuntimeError("unexpected opcode")
return ''.join(output)
>>> sm= difflib.SequenceMatcher(None, "lorem ipsum dolor sit amet", "lorem foo ipsum dolor amet")
>>> show_diff(sm)
'lorem<ins> foo</ins> ipsum dolor <del>sit </del>amet'
This works with strings. You should decide what to do with "replace" opcodes.
Here's an inline differ inspired by @tzot's answer above (also Python 3 compatible):
def inline_diff(a, b):
import difflib
matcher = difflib.SequenceMatcher(None, a, b)
def process_tag(tag, i1, i2, j1, j2):
if tag == 'replace':
return '{' + matcher.a[i1:i2] + ' -> ' + matcher.b[j1:j2] + '}'
if tag == 'delete':
return '{- ' + matcher.a[i1:i2] + '}'
if tag == 'equal':
return matcher.a[i1:i2]
if tag == 'insert':
return '{+ ' + matcher.b[j1:j2] + '}'
assert False, "Unknown tag %r"%tag
return ''.join(process_tag(*t) for t in matcher.get_opcodes())
It's not perfect, for example, it would be nice to expand 'replace' opcodes to recognize the full word replaced instead of just the few different letters, but it's a good place to start.
Sample output:
>>> a='Lorem ipsum dolor sit amet consectetur adipiscing'
>>> b='Lorem bananas ipsum cabbage sit amet adipiscing'
>>> print(inline_diff(a, b))
Lorem{+ bananas} ipsum {dolor -> cabbage} sit amet{- consectetur} adipiscing
difflib.SequenceMatcher will operate on single lines. You can use the "opcodes" to determine how to change the first line to make it the second line.