Python - getting just the difference between strings

a = 'testing this is working \n testing this is working 1 \n'
b = 'testing this is working \n testing this is working 1 \n testing this is working 2'

splitA = set(a.split("\n"))
splitB = set(b.split("\n"))

diff = splitB.difference(splitA)
diff = ", ".join(diff)  # ' testing this is working 2, more things if there were...'

Essentially making each string a set of lines, and taking the set difference - i.e. All things in B that are not in A. Then taking that result and joining it all into one string.

Edit: This is a conveluded way of saying what @ShreyasG said - [x for x if x not in y]...

The easiest Hack, credits @Chris, by using split().

Note : you need to determine which is the longer string, and use that for split.

if len(a)>len(b): 
   res=''.join(a.split(b))             #get diff
else: 
   res=''.join(b.split(a))             #get diff

print(res.strip())                     #remove whitespace on either sides

# driver values

IN : a = 'testing this is working \n testing this is working 1 \n' 
IN : b = 'testing this is working \n testing this is working 1 \n testing this is working 2'

OUT : testing this is working 2

EDIT : thanks to @ekhumoro for another hack using replace, with no need for any of the join computation required.

if len(a)>len(b): 
    res=a.replace(b,'')             #get diff
else: 
    res=b.replace(a,'')             #get diff

This is basically @Godron629's answer, but since I can't comment, I'm posting it here with a slight modification: changing difference for symmetric_difference so that the order of the sets doesn't matter.

a = 'testing this is working \n testing this is working 1 \n'
b = 'testing this is working \n testing this is working 1 \n testing this is working 2'

splitA = set(a.split("\n"))
splitB = set(b.split("\n"))

diff = splitB.symmetric_difference(splitA)
diff = ", ".join(diff)  # ' testing this is working 2, some more things...'