Python Map List of Strings to Integer List

Have a look at ord, which gives the unicode number for a given character:

>>> letters = ['a','b','c','d','e','f','g']
>>> [ord(x) for x in letters]
[97, 98, 99, 100, 101, 102, 103]

So you could do ord(x)-96 to convert a-z to 1-26 (careful about upper case, etc).

l = ['a','b','a','c']
k = [ord(x)-96 for x in l] # [1,2,1,3]

Again, careful about upper case and non-alphabet characters.

In order to answer the edited question, i.e., to map the list of strings to unique integers, one has to first find the unique strings and then do 1-1 mapping of the strings to integers in the original list of strings. For example,

s = ['michael','michael','alice','carter']

then unique strings are {'michael','alice','carter'}. Now, convert these strings to integers by 1-1 mapping like {'michael','alice','carter'} =[1,2,3] using dictionary {'michael':1,'alice':2,'carter':3}. In the third step, loop through the original list of strings; search the string in the dictionary for the corresponding integer and replace the string by that integer.

s=['michael','michael','alice','carter']

mydict={}
i = 0
for item in s:
    if(i>0 and item in mydict):
        continue
    else:    
       i = i+1
       mydict[item] = i

k=[]
for item in s:
    k.append(mydict[item])

Output:

k=[1, 1, 2, 3]

How about using Pandas?

import pandas as pd
l = ['michael','michael','alice','carter']
pd.Series(l).astype('category').cat.codes.values