Random Word Generator #2

I refactored your answer and after some debugging I got it to work. Sorry I couldn't just do a tweak on it to fix it. I believe it does not allow a word to end in "qu" or "q".

public void WordFinder()
{
    bool isWord = false;
    Random rnd = new Random();
    string[] consonants = { "b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z" };
    string[] vowels = { "a", "e", "i", "o", "u" };


    while (isWord == false)
    {
        string word = "";

        Console.WriteLine("Pick the length of a word");
        int requestedLength = Convert.ToInt32(Console.ReadLine());

        // Generate the word in consonant / vowel pairs
        while (word.Length < requestedLength)
        {
            if (requestedLength != 1)
            {
                // Add the consonant
                string consonant = GetRandomLetter(rnd, consonants);

                if (consonant == "q" && word.Length + 3 <= requestedLength) // check +3 because we'd add 3 characters in this case, the "qu" and the vowel.  Change 3 to 2 to allow words that end in "qu"
                {
                    word += "qu";
                }
                else
                {
                    while( consonant == "q")
                    {
                        // Replace an orphaned "q"
                        consonant = GetRandomLetter(rnd, consonants); 
                    }

                    if (word.Length + 1 <= requestedLength)
                    {
                        // Only add a consonant if there's enough room remaining
                        word += consonant;
                    }
                }
            }

            if (word.Length + 1 <= requestedLength)
            {
                // Only add a vowel if there's enough room remaining
                word += GetRandomLetter(rnd, vowels);
            }
        }

        Console.WriteLine(word);
        Console.WriteLine("Is this a word? (y/n)");
        string q = Console.ReadLine().ToLower();

        if (q == "y" || q == "yes")
        {
            isWord = true;
        }
    }
}

private static string GetRandomLetter(Random rnd, string[] letters)
{
    return letters[rnd.Next(0, letters.Length - 1)];
}

Edit: However, that's still pretty unruly. How about generating a random string, and then replacing "q" with "qu" after you're done?

public string WordFinder2(int requestedLength)
{
    Random rnd = new Random();
    string[] consonants = { "b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z" };
    string[] vowels = { "a", "e", "i", "o", "u" };

    string word = "";

    if (requestedLength == 1)
    {
        word = GetRandomLetter(rnd, vowels);
    }
    else
    {
        for (int i = 0; i < requestedLength; i+=2)
        {
            word += GetRandomLetter(rnd, consonants) + GetRandomLetter(rnd, vowels);
        }

        word = word.Replace("q", "qu").Substring(0, requestedLength); // We may generate a string longer than requested length, but it doesn't matter if cut off the excess.
    }

    return word;
}

private static string GetRandomLetter(Random rnd, string[] letters)
{
    return letters[rnd.Next(0, letters.Length - 1)];
}