regex to match repeated consonant
Try this:
([b-df-hj-np-tv-z])\1{2,}
Explanation:
[b-df-hj-np-tv-z]
are all the consonants\1
is the back reference to the 1st group (ie the same character){2,}
means "2 or more of the preceding term", making 3 or more in all
See live demo.
This is about the shortest regex I could think of to do it:
(?i)([b-z&&[^eiou]])\1\1+
This uses a regex character class subtraction to exclude vowels.
I didn't have to mention "a" because I started the range from "b".
Using (?i)
makes the regex case insensitive.
See a live demo.
There may be shortcuts in certain regex libraries but you can always...
b{3,}|c{3,}|d{3,}...
Some libs for example let you match using a back reference which may be a tad cleaner...
(bcd...)\1{2,}