Regular Expressions: how to accept any symbol

To accept any symbol, .* should do the trick.

E.g.: fields[i] = fields[i].replaceAll("\\<.*\\>", "");

Any char in regexp is "." the "*" - is quantifier, how many. Thus if you want just one char, then use "." (dot) and that's it.

Try this [^\>]* (any character that isn't >)