Remove all ANSI colors/styles from strings

The escape character is \u001b, and the sequence from [ until first m is encountered is the styling. You just need to remove that. So, replace globally using the following pattern:

/\u001b\[.*?m/g

Thus,

'\u001b[1m\u001b[38;5;231mHello World\u001b[0m\u001b[22m'.replace(/\u001b\[.*?m/g, '')

The regex you should be using is

/[\u001b\u009b][[()#;?]*(?:[0-9]{1,4}(?:;[0-9]{0,4})*)?[0-9A-ORZcf-nqry=><]/g

This matches most of the ANSI escape codes, beyond just colors, including the extended VT100 codes, archaic/proprietary printer codes, etc.

Note that the \u001b in the above regex may not work for your particular library (even though it should); check out my answer to a similar question regarding acceptable escape characters if it doesn't.

If you don't like regexes, you can always use the strip-ansi package.

For instance, the string jumpUpAndRed below contains ANSI codes for jumping to the previous line, writing some red text, and then going back to the beginning of the next line - of which require suffixes other than m.

var jumpUpAndRed = "\x1b[F\x1b[31;1mHello, there!\x1b[m\x1b[E";
var justText = jumpUpAndRed.replace(
    /[\u001b\u009b][[()#;?]*(?:[0-9]{1,4}(?:;[0-9]{0,4})*)?[0-9A-ORZcf-nqry=><]/g, '');
console.log(justText);