Remove parent if it doesn't have a child with specific class
You can use :not with :has:
$(() => $('.parent:not(:has(.yes))').remove()).parent{ background: orange; height: 100px; width: 100px; margin: 10px; }<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class='parent one'>
<div class='yes'>Child of one</div>
<div class='yes'>Child of one</div>
<div class='yes'>Child of one</div>
</div>
<div class='parent two'>
<div>Child of two</div>
<div>Child of two</div>
<div>Child of two</div>
</div>
<div class='parent three'>
<div>Child of three</div>
<div>Child of three</div>
<div class='yes'>Child of three</div>
</div>You could create a selector as a combination of :not and :has and then use remove method. So this will select all elements with .parent class that do not have child element with .yes class.
$('.parent:not(:has(.yes))')
$('.parent:not(:has(.yes))').remove()<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class='parent one'>
<div class='yes'>one</div>
<div class='yes'></div>
<div class='yes'></div>
</div>
<div class='parent two'>
<div>two</div>
<div></div>
<div></div>
</div>
<div class='parent three'>
<div>three</div>
<div></div>
<div class='yes'></div>
</div>