Return a requests.Response object from Flask

Ok, found it:

If a tuple is returned the items in the tuple can provide extra information. Such tuples have to be in the form (response, status, headers). The status value will override the status code and headers can be a list or dictionary of additional header values.

(Flask docs.)

So

return (resp.text, resp.status_code, resp.headers.items())

seems to do the trick.

I ran into the same scenario, except that in my case my requests.models.Response contained an attachment. This is how I got it to work:

return send_file(BytesIO(result.content), mimetype=result.headers['Content-Type'], as_attachment=True)

Using text or content property of the Response object will not work if the server returns encoded data (such as content-encoding: gzip) and you return the headers unchanged. This happens because text and content have been decoded, so there will be a mismatch between the header-reported encoding and the actual encoding.

According to the documentation:

In the rare case that you’d like to get the raw socket response from the server, you can access r.raw. If you want to do this, make sure you set stream=True in your initial request.

and

Response.raw is a raw stream of bytes – it does not transform the response content.

So, the following works for gzipped data too:

esreq = requests.Request(method=request.method, url=url,
                         headers=request.headers, data=request.data)
resp = requests.Session().send(esreq.prepare(), stream=True)
return resp.raw.read(), resp.status_code, resp.headers.items()

If you use a shortcut method such as get, it's just:

resp = requests.get(url, stream=True)
return resp.raw.read(), resp.status_code, resp.headers.items()

Flask can return an object of type flask.wrappers.Response.

You can create one of these from your requests.models.Response object r like this:

from flask import Response

return Response(
    response=r.reason,
    status=r.status_code,
    headers=dict(r.headers)
)