Round a float UP to next odd integer

You need to ceil before dividing:

import numpy as np

def round_up_to_odd(f):
    return np.ceil(f) // 2 * 2 + 1

What about:

def round_up_to_odd(f):
    f = int(np.ceil(f))
    return f + 1 if f % 2 == 0 else f

The idea is first to round up to an integer and then check if the integer is odd or even.