selecting attribute values from lxml

As a possible useful addition, this is how to get the value of an attribute in the case that the element has more than one, and it is the only difference with respect to another element. E.g., given the following file.xml:

<?xml version ="1.0" encoding="UTF-8"?>
    <level1>
      <level2 first_att='att1' second_att='foo'>8</level2>
      <level2 first_att='att2' second_att='bar'>8</level2>
    </level1>

One can access the attribute 'bar' with:

import lxml.etree as etree
tree = etree.parse("test_file.xml")
print tree.xpath("//level1/level2[@first_att='att2']/@second_att")[0]

find and findall only implement a subset of XPath. Their presence is meant to provide compatibility with other ElementTree implementations (like ElementTree and cElementTree).

The xpath method, in contrast, provides full access to XPath 1.0:

print customer.xpath('./@NAME')[0]

However, you could instead use get:

print customer.get('NAME')

or attrib:

print customer.attrib['NAME']