Shell - How to find directory of some command?

If you're using Bash or zsh, use this:

type -a lshw

This will show whether the target is a builtin, a function, an alias or an external executable. If the latter, it will show each place it appears in your PATH.

bash$ type -a lshw
lshw is /usr/bin/lshw
bash$ type -a ls
ls is aliased to `ls --color=auto'
ls is /bin/ls
bash$ zsh
zsh% type -a which
which is a shell builtin
which is /usr/bin/which

In Bash, for functions type -a will also display the function definition. You can use declare -f functionname to do the same thing (you have to use that for zsh, since type -a doesn't).

Like this:

which lshw

To see all of the commands that match in your path:

which -a lshw 

PATH is an environment variable, and can be displayed with the echo command:

echo $PATH

It's a list of paths separated by the colon character ':'

The which command tells you which file gets executed when you run a command:

which lshw

sometimes what you get is a path to a symlink; if you want to trace that link to where the actual executable lives, you can use readlink and feed it the output of which:

readlink -f $(which lshw)

The -f parameter instructs readlink to keep following the symlink recursively.

Here's an example from my machine:

$ which firefox
/usr/bin/firefox

$ readlink -f $(which firefox)
/usr/lib/firefox-3.6.3/firefox.sh