Should I use .done() and .fail() for new jQuery AJAX code instead of success and error

As stated by user2246674, using success and error as parameter of the ajax function is valid.

To be consistent with precedent answer, reading the doc :

Deprecation Notice:

The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks will be deprecated in jQuery 1.8. To prepare your code for their eventual removal, use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.

If you are using the callback-manipulation function (using method-chaining for example), use .done(), .fail() and .always() instead of success(), error() and complete().

I want to add something on @Michael Laffargue's post:

jqXHR.done() is faster!

jqXHR.success() have some load time in callback and sometimes can overkill script. I find that on hard way before.

UPDATE:

Using jqXHR.done(), jqXHR.fail() and jqXHR.always() you can better manipulate with ajax request. Generaly you can define ajax in some variable or object and use that variable or object in any part of your code and get data faster. Good example:

/* Initialize some your AJAX function */
function call_ajax(attr){
    var settings=$.extend({
        call            : 'users',
        option          : 'list'
    }, attr );

    return $.ajax({
        type: "POST",
        url: "//exapmple.com//ajax.php",
        data: settings,
        cache : false
    });
}

/* .... Somewhere in your code ..... */

call_ajax({
    /* ... */
    id : 10,
    option : 'edit_user'
    change : {
          name : 'John Doe'
    }
    /* ... */
}).done(function(data){

    /* DO SOMETHING AWESOME */

});

In simple words

$.ajax("info.txt").done(function(data) {
  alert(data);
}).fail(function(data){
  alert("Try again champ!");
});

if its get the info.text then it will alert and whatever function you add or if any how unable to retrieve info.text from the server then alert or error function.