Swap array values with php

Try this:

$a = array(
    0 => 'contact',
    1 => 'home',
    2 => 'projects'
);
$temp = $a[0];
$a[0] = $a[1];
$a[1] = $temp;

Just use a temp variable to hold one value as you swap the other. Then restore the first with the temp variable. For numbers there are other methods that don't require the use of temp variables but here it's the best (only?) way.

$a = array(
    0 => 'contact',
    1 => 'home',
    2 => 'projects'
);

print_r($a);
Array ( [0] => contact [1] => home [2] => projects )

$tmp = $a[0];
$a[0] = $a[1];
$a[1] = $tmp;

print_r($a);
Array ( [0] => home [1] => contact [2] => projects )

In PHP 7.1+ syntax, you can use this

[$Array[$a], $Array[$b]] = [$Array[$b], $Array[$a]];

I wrote simple function array_swap: swap two elements between positions swap_a & swap_b.

function array_swap(&$array,$swap_a,$swap_b){
   list($array[$swap_a],$array[$swap_b]) = array($array[$swap_b],$array[$swap_a]);
}

For OP question (for example):

$items = array(
  0 => 'contact',
  1 => 'home',
  2 => 'projects'
);

array_swap($items,0,1);
var_dump($items);
// OUTPUT

array(3) {
   [0]=> string(4) "home"
   [1]=> string(7) "contact"
   [2]=> string(8) "projects"
 }

Update Since PHP 7.1 it's possible to do it like:

$items = [
  0 => 'contact',
  1 => 'home',
  2 => 'projects'
];

[$items[0], $items[1]] = [$items[1], $items[0]];

var_dump($items);
// OUTPUT

array(3) {
   [0]=> string(4) "home"
   [1]=> string(7) "contact"
   [2]=> string(8) "projects"
 }

It's possible through Symmetric array destructuring.