Which iomanip manipulators are 'sticky'?
setw() only affects the next insertion. That's just the way setw() behaves. The behavior of setw() is the same as ios_base::width(). I got my setw() information from cplusplus.com.
You can find a full list of manipulators here. From that link, all the stream flags should stay set until changed by another manipulator. One note about the left, right and internal manipulators: They are like the other flags and do persist until changed. However, they only have an effect when the width of the stream is set, and the width must be set every line. So, for example
cout.width(6);
cout << right << "a" << endl;
cout.width(6);
cout << "b" << endl;
cout.width(6);
cout << "c" << endl;
would give you
> a
> b
> c
but
cout.width(6);
cout << right << "a" << endl;
cout << "b" << endl;
cout << "c" << endl;
would give you
> a
>b
>c
The Input and Output manipulators are not sticky and only occur once where they are used. The parameterized manipulators are each different, here's a brief description of each:
setiosflags lets you manually set flags, a list of which can be found here, so it is sticky.
resetiosflags behaves similar to setiosflags except it unsets the specified flags.
setbase sets the base of integers inserted into the stream (so 17 in base 16 would be "11", and in base 2 would be "10001").
setfill sets the fill character to insert in the stream when setw is used.
setprecision sets the decimal precision to be used when inserting floating point values.
setw makes only the next insertion the specified width by filling with the character specified in setfill
Important notes from the comments below:
By Martin:
@Chareles: Then by this requirement all manipulators are sticky. Except setw which seems to be reset after use.
By Charles:
Exactly! and the only reason that setw appears to behave differently is because there are requirements on formatted output operations to explicitly .width(0) the output stream.
The following is the discussion that lead to the above conclusion:
Looking at the code the following manipulators return an object rather than a stream:
setiosflags
resetiosflags
setbase
setfill
setprecision
setw
This is a common technique to apply an operation to only the next object that is applied to the stream. Unfortunately this does not preclude them from being sticky. Tests indicate that all of them except setw are sticky.
setiosflags: Sticky
resetiosflags:Sticky
setbase: Sticky
setfill: Sticky
setprecision: Sticky
All the other manipulators return a stream object. Thus any state information they change must be recorded in the stream object and is thus permanent (until another manipulator changes the state). Thus the following manipulators must be Sticky manipulators.
[no]boolalpha
[no]showbase
[no]showpoint
[no]showpos
[no]skipws
[no]unitbuf
[no]uppercase
dec/ hex/ oct
fixed/ scientific
internal/ left/ right
These manipulators actually perform an operation on the stream itself rather than the stream object (Though technically the stream is part of the stream objects state). But I do not believe they affect any other part of the stream objects state.
ws/ endl/ ends/ flush
The conclusion is that setw seems to be the only manipulator on my version that is not sticky.
For Charles a simple trick to affect only the next item in the chain:
Here is an Example how an object can be used to temporaily change the state then put it back by the use of an object:
#include <iostream>
#include <iomanip>
// Private object constructed by the format object PutSquareBracket
struct SquareBracktAroundNextItem
{
SquareBracktAroundNextItem(std::ostream& str)
:m_str(str)
{}
std::ostream& m_str;
};
// New Format Object
struct PutSquareBracket
{};
// Format object passed to stream.
// All it does is return an object that can maintain state away from the
// stream object (so that it is not STICKY)
SquareBracktAroundNextItem operator<<(std::ostream& str,PutSquareBracket const& data)
{
return SquareBracktAroundNextItem(str);
}
// The Non Sticky formatting.
// Here we temporariy set formating to fixed with a precision of 10.
// After the next value is printed we return the stream to the original state
// Then return the stream for normal processing.
template<typename T>
std::ostream& operator<<(SquareBracktAroundNextItem const& bracket,T const& data)
{
std::ios_base::fmtflags flags = bracket.m_str.flags();
std::streamsize currentPrecision = bracket.m_str.precision();
bracket.m_str << '[' << std::fixed << std::setprecision(10) << data << std::setprecision(currentPrecision) << ']';
bracket.m_str.flags(flags);
return bracket.m_str;
}
int main()
{
std::cout << 5.34 << "\n" // Before
<< PutSquareBracket() << 5.34 << "\n" // Temp change settings.
<< 5.34 << "\n"; // After
}
> ./a.out
5.34
[5.3400000000]
5.34
The reason that width does not appear to be 'sticky' is that certain operations are guaranteed to call .width(0) on an output stream. Those are:
21.3.7.9 [lib.string.io]:
template<class charT, class traits, class Allocator>
basic_ostream<charT, traits>&
operator<<(basic_ostream<charT, traits>& os,
const basic_string<charT,traits,Allocator>& str);
22.2.2.2.2 [lib.facet.num.put.virtuals]: All do_put overloads for the num_put template. These are used by overloads of operator<< taking a basic_ostream and a built in numeric type.
22.2.6.2.2 [lib.locale.money.put.virtuals]: All do_put overloads for the money_put template.
27.6.2.5.4 [lib.ostream.inserters.character]: Overloads of operator<< taking a basic_ostream and one of the char type of the basic_ostream instantiation or char, signed char or unsigned char or pointers to arrays of these char types.
To be honest I'm not sure of the rationale for this, but no other states of an ostream should be reset by formatted output functions. Of course, things like badbit and failbit may be set if there is a failure in the output operation, but that should be expected.
The only reason that I can think of for resetting the width is that it might be surprising if, when trying to output some delimited fields, your delimiters were padded.
E.g.
std::cout << std::setw(6) << 4.5 << '|' << 3.6 << '\n';
" 4.5 | 3.6 \n"
To 'correct' this would take:
std::cout << std::setw(6) << 4.5 << std::setw(0) << '|' << std::setw(6) << 3.6 << std::setw(0) << '\n';
whereas with a resetting width, the desired output can be generated with the shorter:
std::cout << std::setw(6) << 4.5 << '|' << std::setw(6) << 3.6 << '\n';