Array of objects return object when condition matched
You can make use of .filter()
and check if the filtered array has a length of more than 0
:
let array = [
{id: 'hyu', email: '[email protected]', password: 123},
{id: 'rft', email: '[email protected]', password: 456},
{id: 'ght', email: '[email protected]', password: 789},
{id: 'kui', email: '[email protected]', password: 679}
]
let filtered = array.filter(row => row.email === '[email protected]');
console.log(filtered);
if (filtered.length > 0) { /* mail exists */ }
else { /* mail does not exist */ }
Assuming the email is unique, you can use find()
. This will return null
if not email does not exist.
let array = [{"id":"hyu","email":"[email protected]","password":123},{"id":"rft","email":"[email protected]","password":456},{"id":"ght","email":"[email protected]","password":789},{"id":"kui","email":"[email protected]","password":679}];
const getObject = (email, array) => {
return array.find(function(el) {
return el.email === email;
}) || null;
};
console.log(getObject("[email protected]", array));
Shorter Version:
const getObject = (email, array) => array.find(el => el.email === email ) || null;