Compute Median of Values Stored In Vector - C++?

const int DIVISOR = 2;

Don't do this. It just makes your code more convoluted. You've probably read guidelines about not using magic numbers, but evenness vs. oddness of numbers is a fundamental property, so abstracting this out provides no benefit but hampers readability.

if ((hWScores.size() % DIVISOR) == 0)
{
    median = ((hWScores.begin() + hWScores.size()) + (hWScores.begin() + (hWScores.size() + 1))) / DIVISOR);

You're taking an iterator to the end of the vector, taking another iterator that points one past the end of the vector, adding the iterators together (which isn't an operation that makes sense), and then dividing the resulting iterator (which also doesn't make sense). This is the more complicated case; I'll explain what to do for the odd-sized vector first and leave the even-sized case as an exercise for you.

}
else 
{
    median = ((hWScores.begin() + hWScores.size()) / DIVISOR)

Again, you're dividing an iterator. What you instead want to do is to increment an iterator to the beginning of the vector by hWScores.size() / 2 elements:

    median = *(hWScores.begin() + hWScores.size() / 2);

And note that you have to dereference iterators to get values out of them. It'd be more straightforward if you used indices:

    median = hWScores[hWScores.size() / 2];

There is no need to completely sort the vector: std::nth_element can do enough work to put the median in the correct position. See my answer to this question for an example.

Of course, that doesn't help if your teacher forbids using the right tool for the job.

You are doing an extra division and overall making it a bit more complex than it needs to be. Also, there's no need to create a DIVISOR when 2 is actually more meaningful in context.

double CalcMHWScore(vector<int> scores)
{
  size_t size = scores.size();

  if (size == 0)
  {
    return 0;  // Undefined, really.
  }
  else
  {
    sort(scores.begin(), scores.end());
    if (size % 2 == 0)
    {
      return (scores[size / 2 - 1] + scores[size / 2]) / 2;
    }
    else 
    {
      return scores[size / 2];
    }
  }
}