How do I use matplotlib autopct?
You can do:
plt.pie(values, labels=labels, autopct=lambda p : '{:.2f}% ({:,.0f})'.format(p,p * sum(values)/100))
autopct
enables you to display the percent value using Python string formatting. For example, if autopct='%.2f'
, then for each pie wedge, the format string is '%.2f'
and the numerical percent value for that wedge is pct
, so the wedge label is set to the string '%.2f'%pct
.
import matplotlib.pyplot as plt
plt.figure()
values = [3, 12, 5, 8]
labels = ['a', 'b', 'c', 'd']
plt.pie(values, labels=labels, autopct='%.2f')
plt.show()
yields
You can do fancier things by supplying a callable to autopct
. To display both the percent value and the original value, you could do this:
import matplotlib.pyplot as plt
# make the pie circular by setting the aspect ratio to 1
plt.figure(figsize=plt.figaspect(1))
values = [3, 12, 5, 8]
labels = ['a', 'b', 'c', 'd']
def make_autopct(values):
def my_autopct(pct):
total = sum(values)
val = int(round(pct*total/100.0))
return '{p:.2f}% ({v:d})'.format(p=pct,v=val)
return my_autopct
plt.pie(values, labels=labels, autopct=make_autopct(values))
plt.show()
Again, for each pie wedge, matplotlib supplies the percent value pct
as the argument, though this time it is sent as the argument to the function my_autopct
. The wedge label is set to my_autopct(pct)
.