How to find a whole word in a String in java

Hope this works for you:

String string = "I will come and meet you at the 123woods";
String keyword = "123woods";

Boolean found = Arrays.asList(string.split(" ")).contains(keyword);
if(found){
      System.out.println("Keyword matched the string");
}

http://codigounico.blogspot.com/

Use regex + word boundaries as others answered.

"I will come and meet you at the 123woods".matches(".*\\b123woods\\b.*");

will be true.

"I will come and meet you at the 123woods".matches(".*\\bwoods\\b.*");

will be false.

How about something like Arrays.asList(String.split(" ")).contains("xx")?

See String.split() and How can I test if an array contains a certain value.

The example below is based on your comments. It uses a List of keywords, which will be searched in a given String using word boundaries. It uses StringUtils from Apache Commons Lang to build the regular expression and print the matched groups.

String text = "I will come and meet you at the woods 123woods and all the woods";

List<String> tokens = new ArrayList<String>();
tokens.add("123woods");
tokens.add("woods");

String patternString = "\\b(" + StringUtils.join(tokens, "|") + ")\\b";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(text);

while (matcher.find()) {
    System.out.println(matcher.group(1));
}

If you are looking for more performance, you could have a look at StringSearch: high-performance pattern matching algorithms in Java.