How to get a distinct value of a row with sequelize?

You can specify distinct for one or more attributes using Sequelize.fn

Project.findAll({
    attributes: [
        // specify an array where the first element is the SQL function and the second is the alias
        [Sequelize.fn('DISTINCT', Sequelize.col('country')) ,'country'],

        // specify any additional columns, e.g. country_code
        // 'country_code'

    ]
}).then(function(country) {  })

Try with this: https://github.com/sequelize/sequelize/issues/2996#issuecomment-141424712

Project.aggregate('country', 'DISTINCT', { plain: false })
.then(...)

I ended up using grouping like this:

Project.findAll({
  attributes: ['country'],
  group: ['country']
}).then(projects => 
  projects.map(project => project.country)
);

It results into distinct models you can nicely iterate.

Link in previous answer helped little bit: https://github.com/sequelize/sequelize/issues/2996#issuecomment-141424712

This works well too, but generating response with DISTINCT as column name:

Project.aggregate('country', 'DISTINCT', { plain: false })
  .then(...)