How to make the this brace bigger? "}"
I would suggested aligned
(or gathered
) for the two blocks on either side of the brace. In any case you can use a rule of zero width to give a minimum size to the brace. In the following the brace size has been made unnaturally large for demonstration purposes.
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation*}
\left .
\begin{aligned}
2 \beta_{r,j}^{(l)} &= \beta_{r,j}^{l-1} + \beta_{R+r,j}^{(l-1)}
\epsilon_{m}^{j}
\\[1ex]
2 \beta_{r,m+j}^{(l)} &= \beta_{r,j}^{l-1} +
\beta_{R+r,j}^{(l-1)} \epsilon_{m}^{j}
\end{aligned}
\quad \vrule width 0pt height 7ex \right \}\quad
\begin{aligned}
&r=0,\dots,R-1 \\
&j=0,\dots,m-1 \\
&\epsilon_m = e^{\frac{-2 \pi i}{2^m}}
\end{aligned}
\end{equation*}
\end{document}
You can use array
for LHS also. And the vertical distance can be changed by \\[<dimen>]
.
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation*}
\left .
\begin{array}{r}
2 \beta_{r,j}^{(l)} = \beta_{r,j}^{l-1} + \beta_{R+r,j}^{(l-1)} \epsilon_{m}^{j}
\\[10pt]
2 \beta_{r,m+j}^{(l)} = \beta_{r,j}^{l-1} + \beta_{R+r,j}^{(l-1)} \epsilon_{m}^{j}
\end{array}
\right \}
\begin{array}{l}
r=0,\dots,R-1
\\
j=0,\dots,m-1
\\
\epsilon_m = e^{\frac{-2 \pi i}{2^m}}
\end{array}
\end{equation*}
\end{document}