Conditionally use view in SwiftUI

Anyway, the issue still exists. Thinking mvvm-like all examples on that page breaks it. Logic of UI contains in View. In all cases is not possible to write unit-test to cover logic.

PS. I am still can't solve this.

UPDATE

I am ended with solution,

View file:

import SwiftUI


struct RootView: View {

    @ObservedObject var viewModel: RatesListViewModel

    var body: some View {
        viewModel.makeView()
    }
}


extension RatesListViewModel {

    func makeView() -> AnyView {
        if isShowingEmpty {
            return AnyView(EmptyListView().environmentObject(self))
        } else {
            return AnyView(RatesListView().environmentObject(self))
        }
    }
}

The simplest way to avoid using an extra container like HStack is to annotate your body property as @ViewBuilder, like this:

@ViewBuilder
var body: some View {
    if user.isLoggedIn {
        MainView()
    } else {
        LoginView()
    }
}

You didn't include it in your question but I guess the error you're getting when going without the stack is the following?

Function declares an opaque return type, but has no return statements in its body from which to infer an underlying type

The error gives you a good hint of what's going on but in order to understand it, you need to understand the concept of opaque return types. That's how you call the types prefixed with the some keyword. I didn't see any Apple engineers going deep into that subject at WWDC (maybe I missed the respective talk?), which is why I did a lot of research myself and wrote an article on how these types work and why they are used as return types in SwiftUI.

🔗 What’s this “some” in SwiftUI?

There is also a detailed technical explanation in another

🔗 Stackoverflow post on opaque result types

If you want to fully understand what's going on I recommend reading both.

---

As a quick explanation here:

General Rule:

Functions or properties with an opaque result type (some Type)
must always return the same concrete type.

In your example, your body property returns a different type, depending on the condition:

var body: some View {
    if someConditionIsTrue {
        TabView()
    } else {
        LoginView()
    }
}

If someConditionIsTrue, it would return a TabView, otherwise a LoginView. This violates the rule which is why the compiler complains.

If you wrap your condition in a stack view, the stack view will include the concrete types of both conditional branches in its own generic type:

HStack<ConditionalContent<TabView, LoginView>>

As a consequence, no matter which view is actually returned, the result type of the stack will always be the same and hence the compiler won't complain.

---

💡 Supplemental:

There is actually a view component SwiftUI provides specifically for this use case and it's actually what stacks use internally as you can see in the example above:

ConditionalContent

It has the following generic type, with the generic placeholder automatically being inferred from your implementation:

ConditionalContent<TrueContent, FalseContent>

I recommend using that view container rather that a stack because it makes its purpose semantically clear to other developers.

I needed to embed a view inside another conditionally, so I ended up creating a convenience if function:

extension View {
   @ViewBuilder
   func `if`<Content: View>(_ conditional: Bool, content: (Self) -> Content) -> some View {
        if conditional {
            content(self)
        } else {
            self
        }
    }
}

This does return an AnyView, which is not ideal but feels like it is technically correct because you don't really know the result of this during compile time.

In my case, I needed to embed the view inside a ScrollView, so it looks like this:

var body: some View {
    VStack() {
        Text("Line 1")
        Text("Line 2")
    }
    .if(someCondition) { content in
        ScrollView(.vertical) { content }
    }
}

But you could also use it to conditionally apply modifiers too:

var body: some View {
    Text("Some text")
    .if(someCondition) { content in
        content.foregroundColor(.red)
    }
}

UPDATE: Please read the drawbacks of using conditional modifiers before using this: https://www.objc.io/blog/2021/08/24/conditional-view-modifiers/