How to find duplicates in 2 columns not 1

I found it helpful to add a unqiue index using an "ALTER IGNORE" which removes the duplicates and enforces unique records which sounds like you would like to do. So the syntax would be:

ALTER IGNORE TABLE `table` ADD UNIQUE INDEX(`id`, `another_id`, `one_more_id`);

This effectively adds the unique constraint meaning you will never have duplicate records and the IGNORE deletes the existing duplicates.

You can read more about eh ALTER IGNORE here: http://mediakey.dk/~cc/mysql-remove-duplicate-entries/

Update: I was informed by @Inquisitive that this may fail in versions of MySql> 5.5 :

It fails On MySQL > 5.5 and on InnoDB table, and in Percona because of their InnoDB fast index creation feature [http://bugs.mysql.com/bug.php?id=40344]. In this case first run set session old_alter_table=1 and then the above command will work fine

Update - ALTER IGNORE Removed In 5.7

From the docs

As of MySQL 5.6.17, the IGNORE clause is deprecated and its use generates a warning. IGNORE is removed in MySQL 5.7.

One of the MySQL dev's give two alternatives:

• Group by the unique fields and delete as seen above
• Create a new table, add a unique index, use INSERT IGNORE, ex:

CREATE TABLE duplicate_row_table LIKE regular_row_table;
ALTER TABLE duplicate_row_table ADD UNIQUE INDEX (id, another_id);
INSERT IGNORE INTO duplicate_row_table SELECT * FROM regular_row_table;
DROP TABLE regular_row_table;
RENAME TABLE duplicate_row_table TO regular_row_table;

But depending on the size of your table, this may not be practical

You should set up a composite key between the two fields. This will require a unique stone_id and upcharge_title for each row.

As far as finding the existing duplicates try this:

select   stone_id,
         upcharge_title,
         count(*)
from     your_table
group by stone_id,
         upcharge_title
having   count(*) > 1